25/2(m)=3m^2+25/2

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Solution for 25/2(m)=3m^2+25/2 equation: 


m in (-oo:+oo)

(25/2)*m = 3*m^2+25/2 // - 3*m^2+25/2

(25/2)*m-(3*m^2)-(25/2) = 0

(25/2)*m-3*m^2-25/2 = 0

25/2*m-3*m^2-25/2 = 0

DELTA = (25/2)^2-(-25/2*(-3)*4)

DELTA = 25/4

DELTA > 0

m = ((25/4)^(1/2)-25/2)/(-3*2) or m = (-(25/4)^(1/2)-25/2)/(-3*2)

m = 5/3 or m = 5/2

m in { 5/3, 5/2 }

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